X=-0,02x^2+800x-4000

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Solution for X=-0,02x^2+800x-4000 equation: 



X=-0.02X^2+800X-4000

We move all terms to the left:

X-(-0.02X^2+800X-4000)=0

We get rid of parentheses

0.02X^2-800X+X+4000=0

We add all the numbers together, and all the variables

0.02X^2-799X+4000=0

a = 0.02; b = -799; c = +4000;
Δ = b2-4ac
Δ = -7992-4·0.02·4000
Δ = 638081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-799)-\sqrt{638081}}{2*0.02}=\frac{799-\sqrt{638081}}{0.04}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-799)+\sqrt{638081}}{2*0.02}=\frac{799+\sqrt{638081}}{0.04}
$

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